What is the solubility of barium chromate in parts per million?

At 25C , the molar solubility of barium chromate in water is 1.1*10^-5 M. Please help me with that question. Thank you =)

Answer 1

Convert the molar solubility of barium chromate to grams/L

grams/L = molar solubiity * MW
= 1.1*10^-5M * 253.3207g/mol
grams/L = 2.79*10^-3g/L

ppm = miligrams/L = grams/L * 1000mg/g
= 2.79*10^-3g/L * 1000mg/g
ppm = 7.79ppm

Answer 2

What is the solubility of barium chromate in parts per million?
*parts per million = Grams of Solute/grams of solution X 10^6 (which is ppm)
2.787 x 10^-3g/L x 1L/1000g x 10^6 = 0.02779, or 2.78 x 10^-2ppm

Answer in parts per million to three significant figures =2.78ppm

this is correct for the pearson mastering chemistry question

Answer 3

2.78×10^-3 g/L

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