What is the quotient: (6×4 – 15×3 – 2×2 – 10x – 4) ÷ (3×2 + 2)?

Answer 1

(6x^4 – 15x^3 – 2x^2 – 10x – 4) ÷ (3x^2 + 2)
= (6x^4 – 15x^3 + 4x^2 – 6x^2 – 10x – 4) ÷ (3x^2 + 2)
= (6x^4 + 4x^2 – 15x^3 – 10x – 6x^2 – 4) ÷ (3x^2 + 2)
= 2x^2(3x^2 + 2) – 5x(3x^2 + 2) – 2(3x^2 + 2) ÷ (3x^2 + 2)
= (3x^2 + 2)(2x^2 – 5x – 2) ÷ (3x^2 + 2)
= 2x^2 – 5x – 2 Ans.

Answer 2

you need to use long branch no opposite direction you pick spacers you be attentive to you need to multiply the 1st term (3x^2) by making use of regardless of makes it to regardless of your dividing,so we try to get 6x^4 out,2x^2 cases 3x^2 is 6x^4.Subtract or swap signsto do away with the words often 2x^2-5x+2 —————————— | 3x^2+0x +2|6x^4-15x^3+10x^2-10x+4 -( 6x^4 +0x^3 +4x^2) -15x^3 +6x^2 – (-15x^3 -0x^2-10x) 6x^2 +0x+4 – ( 6x^2 +0x +4) 0 you will nevertheless ought to place in writing interior the 0x for sense purposed Your answer is A

Answer 3

2x^2 . (3x^2 + 2) – 15.x^3 – 6.x^2 – 10.x – 4 =
(2.x^2 – 5.x).(3x^2 + 2) – 6.x^2 – 4 =
(2.x^2 – 5.x – 2).(3x^2 + 2)
so 2.x^2 – 5.x – 2

Answer 4

Tymecia

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