A 0.60-m-diameter vat of liquid is 2.7m deep. The pressure at the bottom of the vat is 1.5atm .
1 atm=101,325 Pa
Get the volume and use the pressure to determine the density.
What is missing is the pressure is absolute or relative. I’ll assume absolute.
V = πr²h = π(0.3)²(2.7) = 0.763 m³
Pfluid = ρgh
Pfluid is pressure in Pa or N/m²
ρ is the density of the fluid in kg/m³
g is the acceleration of gravity 9.8 m/s²
h is the height of the fluid above the object in m
1.5 atm is 1.5•101 kPa
ρ = P/gh = (151.5e3) / (9.8)(2.7) = 5726 kg/m³
(possibly molten tin)
5726 kg/m³ x 0.763 m³ = 4370 kg
the pressure times the area of the bottom of the vat = the total force of gravity on the mass
this is a snap to calculate