The period of a pendulum of length 0.500 m is ?

Answer 1

ans) time period= 1.419 sec

Answer 2

The time period(T) of a simple pendulum is directly proportional to square root of it’s length(l).

T is directly proportional to l

T=2 pi*sqrt(l/g)

T = 2 * pi * sqrt(0.5 / 9.8)

T = 2 * pi *0.2259

T = 1.419 seconds.

Answer 3

T = 2 * pi * sqrt (l / g)

T = 2 * pi * sqrt(0.5 / 9.81)

T = 2 * pi * 0.22576

T = 1.4185 seconds

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