The molecular weight of a gas is __________ g/mol if 6.7 g of the gas occupies 6.3 L at STP.?

A. 24

Answer 1

1 mole of an ideal gas occupies 22.4 L at STP
6.3 L / 22.4 L = 0.28125 mole
6.7 g / 0.28125 mole = 23.8 g/mole
ANSWER: A

Answer 2

One mole of a gas at STP occupies 22.4 liters.

6.7 grams gas/6.3 liters x 22.4 liters/1 mole gas = 23.8 grams /mole

Molecular weight = 23.8

A. 24

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