How much work does this force do as the particle moves along the x-axis from x = 0 to x = L?

**Answer 1**

W = ∫︎ F(x) dx

= F0 ∫︎ e^(-x/L) dx

= F0 [ -L e^(-x/L) ] between 0 and L

= F0 L ( 1 – 1/e )

**Answer 2**

int_0^L (F_0)*exp(-x)/L dx =

Charge Your Knowledge Up

How much work does this force do as the particle moves along the x-axis from x = 0 to x = L?

**Answer 1**

W = ∫︎ F(x) dx

= F0 ∫︎ e^(-x/L) dx

= F0 [ -L e^(-x/L) ] between 0 and L

= F0 L ( 1 – 1/e )

**Answer 2**

int_0^L (F_0)*exp(-x)/L dx =