(Figure 1) shows the angular position of a potter’s wheel.

**Answer 1**

ΔΘ = Θ15-Θ5 = 125-100 = 25 rad

ω = ΔΘ/Δt = (150-50)/10 = 10 rad/sec

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(Figure 1) shows the angular position of a potter’s wheel.

**Answer 1**

ΔΘ = Θ15-Θ5 = 125-100 = 25 rad

ω = ΔΘ/Δt = (150-50)/10 = 10 rad/sec