Two children fight over a 200g stuffed bear. The 25kg boy pulls to the right with a 15N force and the 20kg girls pulls to the left with a 17N force. Ignore all other forces on the bear such as weight.
net force on the bear F = 17 – 15 = 2 N, so that its acceleration is a = F / m = 2 / 0.2 = 10 m/s^2
and direction of this acceleration is to the left in which the force of large magnitude acts.
then we can not find the final velocity unless either time or distance are given.