**Answer 1**

For two gases with molar masses M₁ and M₂, the relative rate of effusion is

(R₁ / R₂) = √(M₂ / M₁)

R₁ = rate of effusion of N₂

R₂ = rate of effusion of Xe

M₁ = molar mass N₂ = 28.014 g/mol

M₂ = molar mass Xe = 131.293 g/mol

(R₁ / R₂) = √(131.293 / 28.014) = 2.16

I arbitrarily wrote the answer to 3 sig figs. I’m not sure how many sig figs you need for your answer.