How much heat is required to warm 1.40 kg of sand from 28.0 C to 100.0 C in Joules? ?

chemistry. please help me how to solve

Answer 1

specific heat = 0.664 J/g°C
Q = mass x specific heat x delta T
Q = 1400 g x 0.664 ( 100.0 – 28.0) = 66931 J

Answer 2

The specific heat of sand is .835 in this case.

Dr.A’s answer is correct if you use .835 as the specific heat.

So it works out to be (1.4 *1000)*(100-28)*.835 = 84168 J

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