Help with my Physic HW?

As shown in the figure , a superball with mass m equal to 50 grams is dropped from a height of h_{rm i} = 1.5 ;{rm m} . It collides with a table, then bounces up to a height of h_{rm f}= 1.0; {rm m} . The duration of the collision (the time during which the superball is in contact with the table) is t_{rm c} = 15 ;{rm ms} . In this problem, take the positive y direction to be upward, and use g = 9.8; {rm m/s^2} for the magnitude of the acceleration due to gravity. Neglect air resistance.

Answer 1

A. Find the y component of the momentum, p_{{rm before}{,}y}, of the ball immediately before the collision.
= 0.05*sq rt(2*9.8*1.5) = 0.27 kg m s^-1

B.Find the y component of the momentum of the ball immediately after the collision, that is, just as it is leaving the table. = 0.05*sq rt(2*9.8*1.0) = 0.22 kg m s^-1

C.Find the y component of the time-averaged force F_{{rm avg}{,}y}, in newtons, that the table exerts on the ball.= [0.22 -(- 0.27)]/0.015 = 32.7 N

D. J_y, the y component of the impulse imparted to the ball during the collision=0.22+0.27=0.49 N

E. Find K_{rm after}-K_{rm before}, the change in the kinetic energy of the ball during the collision, in joules. (0.27^2 – 0.22^2)/(2*0.05) = 0.25 J

Answer 2

Correct, except A. Is -, so -.27
and E is -.25

Source(s): Just completed this problem myself in MasteringPhysics

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