Consider the combination of capacitors shown in the diagram, where C1= 3.00uf , C2= 11.0uf , C3= 3.00uf , and C4= 5.00uf .

**Answer 1**

C2, 3 and 4 are in parallel for the equivalent of 19µF

that is in series with C1 for the equivalent of 3*19/22 = 2.59µF

2) C2 and C6 are in series for the equivalent of 11*3/14 = 2.36

that is in parallel with C3/4/5 for a total of 2.36+5+3+6 = 16.36

that is in series with C1 for the equivalent of 16.36*3/19.36 = 2.54µF

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**Answer 2**

Equivalent Capacitance Mastering Physics

**Answer 3**

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RE:

Find the equivalent capacitance C(a) of the network of capacitors.?

Consider the combination of capacitors shown in the diagram, where C1= 3.00uf , C2= 11.0uf , C3= 3.00uf , and C4= 5.00uf .

DIagram: http://www.cramster.com/answers-feb-08/physics/equ…

Part 2: Two capacitors of capacitance…

**Answer 4**

To get equivalent capacitance in parallel…just add the values like resistors in series