Also please show me your work.

**Answer 1**

x- component of B = 15 cos 60 = 7.5

y- component of B = 15 sin 60 = 15(sq rt 3) / 2

x- component of A = 0

y- component of B = -8

sum x = 7.5

sum y = -8 + 15(sq rt 3) / 2 … use tan T (T = theta)

tan T = [-8 + 15(sq rt 3) / 2] / 7.5

T = inv tan [-8 + 15(sq rt 3) / 2] / 7.5 = 33.639 degrees << answer