During the discharge of an alkaline battery, 4.90g of Zn are consumed at the anode of the battery.
each zinc atom transfers two electrons
4.90 g * 1 mol Zn / 65.39 g * 2 mol e- / 1 mol Zn = 0.14987 mol e-
a mole of charge is called a Faraday
and there are 96485 C/F
0.14987 F * 96485 C/F = 1.45E4 C to 3 sig figs
If someone gives you a good response,
please consider giving a best answer.
This is the only reward we get.