Combustion between Propane and Oxygen?

The balanced reaction is as follows: C3H8+5O2→3CO2+4H2O

Answer 1

The belated picture shows 3 molecules of propane and 10 molecules of oxygen.

10 molecules of oxygen would react completely with 10 x (1/5) = 2 molecules of propane, but there is more propane present than that, so propane is in excess and O2 is the limiting reactant.

(10 molecules of O2) x (3 mol CO2 / 5 mol O2) = 6 molecules CO2
(10 molecules of O2) x (4 mol H2O / 5 mol O2) = 8 molecules H2O
3 molecules C3H8 initially – 2 molecules C3H8 reacted = 1 molecule C3H8 left over
No molecules of O2 will be left since O2 is the limiting reactant.

[I hope the comments aren’t important. YA won’t show them to me, so I haven’t seen them.]

Answer 2

Matt, you big dope, I’d help you but I can’t. You haven’t given us enough information. When you mention the limiting reagent, you’re telling me that they gave you the quantities of the reactants….which you didn’t give to us so we can’t solve this for you. It’s really pretty simple. For example, suppose you’re given a box of black and white marbles and told to pair them up. You can make pairs until you run out of either the black or the white marbles. Which ever one you run out of is the limiting marble. It stops you from making more pairs. You’ll either have some black or white marbles left unpaired. It’s the same thing here. only the marbles are propane and oxygen. I’m sorry, you haven’t told us how many marbles you have. You just don’t have all your marbles (…..don’t be mad, Matty, it’s just that I’ve got this weird sense of humor. Oh! I used to be, or tried to be, a chemistry teacher. Can you imagine what my poor kids had to put up with?) Tell us the rest of the information and we’ll be glad to help you. There’s lots of intelligent people here. I’m here too.

Answer 3

This is the picture I forgot to attach

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