Calculate the molar solubility of CuX (Ksp=1.27×10^-36) in each of the following.

**Answer 1**

1.27 x 10^-36 =(x)(x)

x = molar solubility=1.13 x 10^-18 M

1.27 x 10^-36 = (0.28+x)(x)

x = 4.54 x 10^-36 M

1.27 x 10^-36 = (x)(0.18+x)

x = 7.06 x 10^-36 M

**Answer 2**

can someone explain HOW they did that?