Calculate the molarity of a solution prepared by diluting 1.85 L of 6.5 M KOH to 11.0 L.?

a. 0.28 M

Answer 1

We can use the following equation:
M1V1 = M2V2

Basically, that says that the value of molarity*volume before should be the same as after the dilution.

Thus,
M1 = 6.5
V1 = 1.85
M2 = ???
V2 = 11.0

Plug and chug away…!

Solve for M2, we get
(6.5)(1.85) = M2(11.0)

M2 = 1.0932 = ~1.1 M

[Answer: C]

Answer 2

Use the equation M1V1=M2V2

m1 = 6.5
v1 = 1.85
v2 = 11.0

and solve for M2 the final molarity.

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