Calculate H+ : a solution in which [OH -] is 140 times greater than [H+]?

Answer 1

Let x = [H+]. Then, [OH-] = 140 x. You know that [H+] X [OH-] = 1 X 10^-14.
So,

(x) (140x) = 1 X 10^-14
140 x^2 = 1 X 10^-14
x^2 = 7.14 X 10^-17
x = 8.45 X 10^-9 M = [H+]

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