Calculate either [H3O+] or [OH-] for the solutions below at 25 degrees C. a, [OH-] = 2.87 x 10-7 M; [H3O] = __M; B. [H3O+] = 8.71 x 10-9 M [?

Answer 1

[OH-] = 2.87×10^-7M
pOH = -log[concentration]
pOH = -log [2.87×10^-7]
pOH = you figure it out. Between 6 and 7 if you did it right.

Your other questions are typed in poorly so I cant decipher what you’re truly asking.

Answer 2

[H3O+] x [OH-] = 1.00 x 10^-14
So, if you have one, just divide it from 1.00 x 10^-14 to get the other.
Taking the ‘a’ problem for example: (1.00 x 10^-14) / (2.87 x 10^-7) = 3.48 x 10^-8

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