Balancing an oxidation reduction reaction?

Complete and balance the following equation:

Answer 1

half-reactions:

BrO3^−(aq)→Br2(l)
N2H4(aq)→N2(g)

balance:

10e- + 12H^+ + 2BrO3^−(aq)→Br2(l) + 6H2O
N2H4(aq)→N2(g) + 4H^+ + 4e-

equalize electrons:

20e- + 24H^+ + 4BrO3^−(aq)→2Br2(l) + 12H2O
5N2H4(aq)→5N2(g) + 20H^+ + 20e-

Add:

4H^+ + 4BrO3^−(aq) + 5N2H4(aq)→2Br2(l) + 5N2(g) + 12H2O

You could put the ions together:

4HBrO3(aq) + 5N2H4(aq)→2Br2(l) + 5N2(g) + 12H2O

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